Y=3x^2-4x+11

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Solution for Y=3x^2-4x+11 equation: 



=3Y^2-4Y+11

We move all terms to the left:

-(3Y^2-4Y+11)=0

We get rid of parentheses

-3Y^2+4Y-11=0

a = -3; b = 4; c = -11;
Δ = b2-4ac
Δ = 42-4·(-3)·(-11)
Δ = -116
Delta is less than zero, so there is no solution for the equation

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